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Consider the following standard heats of formation:
P4O10(s) = -3110 kJ/mol
H2O(l) = -286 kJ/mol
H3PO4(s) = -1279 kJ/mol
Calculate the change in enthalpy for the following process:
P4O10(s) + 6H2O(l) → 4H3PO4(s)
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