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A 500-ML Sample of 2

question 67

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A 50.0-mL sample of 2.0 × 10-4 M CuNO3 is added to 50.0 mL of 4.0 M NaCN. Cu+ reacts with CN- to form the complex ion Cu(CN) 32-: A 50.0-mL sample of 2.0 × 10<sup>-4</sup> M CuNO<sub>3</sub> is added to 50.0 mL of 4.0 M NaCN. Cu<sup>+</sup> reacts with CN<sup>-</sup> to form the complex ion Cu(CN) <sub>3</sub><sup>2-</sup>:   Calculate the solubility of CuBr(s)  (K<sub>sp</sub> = 1.0 × 10<sup>-5</sup>)  in 1.0 L of 1.0 M NaCN. A)  0.33 mol/L B)  1.0 × 10<sup>-6</sup> mol/L C)  1.0 × 10<sup>3</sup> mol/L D)  1.0 mol/L E)  none of these Calculate the solubility of CuBr(s) (Ksp = 1.0 × 10-5) in 1.0 L of 1.0 M NaCN.


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