The Potential Energy of a 0

question 12

Multiple Choice

The potential energy of a 0.20-kg particle moving along the x axis is given by U(x) =(8.0J/m²) x² + (2.0J/m⁴) x^4.
When the particle is at x = 1.0 m it is traveling in the positive x direction with a speed of 5.0 m/s. It next stops momentarily to turn around at x =

• A) 0
• B) -1.1 m
• C) 1.1 m
• D) -2.3 m
• E) 2.3 m

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