Cu₂HgI₄ Is Prepared According to the Equation 2 CuI $\rightarrow$ Cu₂HgI₄

question 10

Multiple Choice

Cu₂HgI₄ is prepared according to the equation 2 CuI + HgI₂ $\rightarrow$ Cu₂HgI₄.When 2.00 g of each reactant are used,which one is the limiting reactant?

• A)Both reactants are limiting
• B)This reaction has no limiting reactant
• C)CuI
• D)HgI₂
• E)Cu₂HgI₄

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