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If 1.020 g of KHC8H₄O₄ (204.23 g/mol) is completely neutralized with 0.200 M KOH,what volume of potassium hydroxide is required? KHC8H₄O₄(aq) + KOH(aq) → k₂C8H₄O₄(aq) + 2 H₂O(l)
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