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In the Reaction 2HgO(s) → 2Hg(l) + O2(g) We Measure

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In the reaction 2HgO(s) → 2Hg(l) + O2(g) we measure the evolution of gas to determine the rate of reaction. At the beginning of the reaction (at 0 minutes) , 0.020 L of O2 is present. After 15 minutes the volume of O2 is 0.35 L. What is the rate of reaction?


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