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What Is the Equilibrium Constant at 25°C for the Following

question 52

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What is the equilibrium constant at 25°C for the following reaction? (R = 8.314 J/K • mol,F = 96,500 C • mol-1)
Sn2+(aq) + Fe(s) What is the equilibrium constant at 25°C for the following reaction? (R = 8.314 J/K • mol,F = 96,500 C • mol<sup>-1</sup>)  Sn<sup>2+</sup>(aq) + Fe(s)    Sn(s) + Fe<sup>2+</sup>(aq) E°<sub>cell</sub> = 0.30V A) 1.2 × 10<sup>5</sup> B) 1.4 × 10<sup>10</sup> C) 8.6 × 10<sup>-6</sup> D) 7.1 × 10<sup>-11</sup> E) 2.3 × 10<sup>23</sup> Sn(s) + Fe2+(aq) E°cell = 0.30V

Understand the concepts of birthweight categories and their significance for newborn health.
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