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What is the minimum voltage required for the electrolysis of 1.0 M NaCl in neutral solution? 2H2O + 2Cl- (1.0 M) → H2(1 atm) + Cl2(1 atm) + 2OH-(1 × 10-7 M)
Note that
2H2O(l) + 2e- → H2(g) +2OH-(aq) ,E° = -0.83 V,
2H2O(l) + 2e- → H2(g) +2OH-(aq) ,E = -0.41 V([OH-] = 1 × 10-7M) ,
O2(g) + 4H+(aq) + 4e- →2H2O(l) ,E° = +1.23 V,
Cl2(g) + 2e- → 2Cl-(aq) E° = +1.36 V,and
Na+(aq) + e- → Na(s) E° = -2.71 V
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