Iron Packs in a Body-Centered Cubic Structure $\sqrt{2}(126 \mathrm{pm})=178 \mathrm{pm}$ B) 2(126 Pm)= 252 Pm
C)

question 1

Multiple Choice

Iron packs in a body-centered cubic structure.If an iron atom has a radius of 126 pm,what is the distance between lattice points at two opposite corners of the unit cell? (Note: a line drawn between the points would go through the center of the unit cell)

• A) \(\sqrt{2}(126 \mathrm{pm})=178 \mathrm{pm}\)
• B) 2(126 pm)= 252 pm
• C) \(\frac{\sqrt{3}}{2}(126 \mathrm{pm})=109 \mathrm{pm}\)
• D) 4(126 pm)= 504 pm
• E) \(\sqrt{3}(126 \mathrm{pm})=218 \mathrm{pm}\)