Which Is a Correct Method for Determining the Total Number

question 40

Multiple Choice

Which is a correct method for determining the total number of atoms in 123 grams of sulfur trioxide (SO₃) ?

• A) \(123 \mathrm{~g} \mathrm{~SO}_{3}\left(\frac{1 \mathrm{~mol}}{80.07 \mathrm{~g}}\right)\left(\frac{1 \text { atom }}{6.022 \times 10^{23} \mathrm{~mol}}\right)\)
• B) \(123 \mathrm{~g} \mathrm{~SO}_{3}\left(\frac{1 \mathrm{~mol}}{80.07 \mathrm{~g}}\right)\left(\frac{6.022 \times 10^{23} \text { atoms }}{1 \mathrm{~mol}}\right)\)
• C) \(123 \mathrm{~g} \mathrm{~SO}_{3}\left(\frac{1 \mathrm{~mol}}{80.07 \mathrm{~g}}\right)\left(\frac{1 \mathrm{~mol} \mathrm{atoms}}{4 \mathrm{~mol} \mathrm{~SO}_{3}}\right)\left(\frac{6.022 \times 10^{23} \text { atoms }}{1 \mathrm{~mol}}\right)\)
• D) \(123 \mathrm{~g} \mathrm{~SO}_{3}\left(\frac{1 \mathrm{~mol}}{80.07 \mathrm{~g}}\right)\left(\frac{4 \mathrm{~mol} \text { atoms }}{1 \mathrm{~mol} \mathrm{SO}_{3}}\right)\left(\frac{1 \text { atom }}{6.022 \times 10^{23} \mathrm{~mol}}\right)\)
• E) \(123 \mathrm{~g} \mathrm{~SO}_{3}\left(\frac{1 \mathrm{~mol}}{80.07 \mathrm{~g}}\right)\left(\frac{4 \mathrm{~mol} \mathrm{atoms}}{1 \mathrm{~mol} \mathrm{SO}_{3}}\right)\left(\frac{6.022 \times 10^{23} \text { atoms }}{1 \mathrm{~mol}}\right)\)

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