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Calculate for the Electrochemical Cell Pb(s)|PbCl2(s)| Cl-(aq,1

question 68

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Calculate Calculate   for the electrochemical cell Pb(s) |PbCl<sub>2</sub>(s) | Cl<sup>-</sup>(aq,1.0 M) || Fe<sup>3+</sup>(aq,1.0 M) ,Fe<sup>2+</sup>(aq,1.0 M) | Pt(s) . The standard reduction potentials are as follows: Pb<sup>2+</sup>(aq) + 2 e<sup>-</sup> → Pb(s)  E° = -0.126 V PbCl<sub>2</sub>(s) + 2 e<sup>-</sup> → Pb(s) + 2 Cl<sup>-</sup>(aq)  E° = -0.267 V Fe<sup>3+</sup>(aq) + e<sup>-</sup> → Fe<sup>2+</sup>(aq)  E° = +0.771 V Fe<sup>2+</sup>(aq) + e<sup>-</sup> → Fe(s)  E° = -0.44 V A)  -0.504 V B)  -0.062 V C)  +0.504 V D)  +1.038 V E)  +1.604 V for the electrochemical cell Pb(s) |PbCl2(s) | Cl-(aq,1.0 M) || Fe3+(aq,1.0 M) ,Fe2+(aq,1.0 M) | Pt(s) . The standard reduction potentials are as follows:
Pb2+(aq) + 2 e- → Pb(s)
E° = -0.126 V
PbCl2(s) + 2 e- → Pb(s) + 2 Cl-(aq)
E° = -0.267 V
Fe3+(aq) + e- → Fe2+(aq)
E° = +0.771 V
Fe2+(aq) + e- → Fe(s)
E° = -0.44 V


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