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Using the Following Equation for the Combustion of Octane, Calculate

question 49

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Using the following equation for the combustion of octane, calculate the amount of moles of oxygen that reacts with 100.0 g of octane. The molar mass of octane is 114.33 g Using the following equation for the combustion of octane, calculate the amount of moles of oxygen that reacts with 100.0 g of octane. The molar mass of octane is 114.33 g   . The molar mass of carbon dioxide is 44.0095 g   . 2C<sub>8</sub>H<sub>18</sub> + 25O<sub>2</sub> → 16CO<sub>2</sub> + 18H<sub>2</sub>O   H°<sub> </sub>= -11018 kJ A)  18.18 moles B)  6.997 moles C)  14.00 moles D)  8.000 moles E)  10.93 moles . The molar mass of carbon dioxide is 44.0095 g Using the following equation for the combustion of octane, calculate the amount of moles of oxygen that reacts with 100.0 g of octane. The molar mass of octane is 114.33 g   . The molar mass of carbon dioxide is 44.0095 g   . 2C<sub>8</sub>H<sub>18</sub> + 25O<sub>2</sub> → 16CO<sub>2</sub> + 18H<sub>2</sub>O   H°<sub> </sub>= -11018 kJ A)  18.18 moles B)  6.997 moles C)  14.00 moles D)  8.000 moles E)  10.93 moles . 2C8H18 + 25O2 → 16CO2 + 18H2O Using the following equation for the combustion of octane, calculate the amount of moles of oxygen that reacts with 100.0 g of octane. The molar mass of octane is 114.33 g   . The molar mass of carbon dioxide is 44.0095 g   . 2C<sub>8</sub>H<sub>18</sub> + 25O<sub>2</sub> → 16CO<sub>2</sub> + 18H<sub>2</sub>O   H°<sub> </sub>= -11018 kJ A)  18.18 moles B)  6.997 moles C)  14.00 moles D)  8.000 moles E)  10.93 moles = -11018 kJ


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