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Use the Standard Reaction Enthalpies Given Below to Determine

question 97

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Use the standard reaction enthalpies given below to determine Use the standard reaction enthalpies given below to determine   H° for the following reaction: 4SO<sub>3</sub>(g)  → 4S(s)  + 6O<sub>2</sub>(g)    H°<sub> </sub>= ? Given: SO<sub>2</sub>(g)  → S(s)  + O<sub>2</sub>(g)    H°<sub> </sub>= +296.8 kJ 2SO<sub>2</sub>(g)  + O<sub>2</sub>(g)  → 2SO<sub>3</sub>(g)    H°<sub> </sub>= -197.8 kJ A)  -494.6 kJ mol<sup>-1</sup> B)  -692.4 kJ mol<sup>-1</sup> C)  -791.4 kJ mol<sup>-1</sup> D)  1583 kJ mol<sup>-1</sup> E)  -293.0 kJ mol<sup>-1</sup> H° for the following reaction: 4SO3(g) → 4S(s) + 6O2(g) Use the standard reaction enthalpies given below to determine   H° for the following reaction: 4SO<sub>3</sub>(g)  → 4S(s)  + 6O<sub>2</sub>(g)    H°<sub> </sub>= ? Given: SO<sub>2</sub>(g)  → S(s)  + O<sub>2</sub>(g)    H°<sub> </sub>= +296.8 kJ 2SO<sub>2</sub>(g)  + O<sub>2</sub>(g)  → 2SO<sub>3</sub>(g)    H°<sub> </sub>= -197.8 kJ A)  -494.6 kJ mol<sup>-1</sup> B)  -692.4 kJ mol<sup>-1</sup> C)  -791.4 kJ mol<sup>-1</sup> D)  1583 kJ mol<sup>-1</sup> E)  -293.0 kJ mol<sup>-1</sup> = ?
Given:
SO2(g) → S(s) + O2(g) Use the standard reaction enthalpies given below to determine   H° for the following reaction: 4SO<sub>3</sub>(g)  → 4S(s)  + 6O<sub>2</sub>(g)    H°<sub> </sub>= ? Given: SO<sub>2</sub>(g)  → S(s)  + O<sub>2</sub>(g)    H°<sub> </sub>= +296.8 kJ 2SO<sub>2</sub>(g)  + O<sub>2</sub>(g)  → 2SO<sub>3</sub>(g)    H°<sub> </sub>= -197.8 kJ A)  -494.6 kJ mol<sup>-1</sup> B)  -692.4 kJ mol<sup>-1</sup> C)  -791.4 kJ mol<sup>-1</sup> D)  1583 kJ mol<sup>-1</sup> E)  -293.0 kJ mol<sup>-1</sup> = +296.8 kJ
2SO2(g) + O2(g) → 2SO3(g) Use the standard reaction enthalpies given below to determine   H° for the following reaction: 4SO<sub>3</sub>(g)  → 4S(s)  + 6O<sub>2</sub>(g)    H°<sub> </sub>= ? Given: SO<sub>2</sub>(g)  → S(s)  + O<sub>2</sub>(g)    H°<sub> </sub>= +296.8 kJ 2SO<sub>2</sub>(g)  + O<sub>2</sub>(g)  → 2SO<sub>3</sub>(g)    H°<sub> </sub>= -197.8 kJ A)  -494.6 kJ mol<sup>-1</sup> B)  -692.4 kJ mol<sup>-1</sup> C)  -791.4 kJ mol<sup>-1</sup> D)  1583 kJ mol<sup>-1</sup> E)  -293.0 kJ mol<sup>-1</sup> = -197.8 kJ

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