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Use the H° and H° information Provided to Calculate

question 65

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Use the Use the H° and H°<sub> </sub>information provided to calculate H° for SO<sub>3</sub>(g) : H°<sub> </sub>(kJ ) 2SO<sub>2</sub>(g) + O<sub>2</sub>(g) → 2SO<sub>3</sub>(g) H°<sub> </sub>= -198 kJ SO<sub>2</sub>(g) -297 A) -792 kJ mol<sup>-1</sup> B) -248 kJ mol<sup>-1</sup> C) -495 kJ mol<sup>-1</sup> D) -578 kJ mol<sup>-1</sup> E) -396 kJ mol<sup>-1</sup> H° and Use the H° and H°<sub> </sub>information provided to calculate H° for SO<sub>3</sub>(g) : H°<sub> </sub>(kJ ) 2SO<sub>2</sub>(g) + O<sub>2</sub>(g) → 2SO<sub>3</sub>(g) H°<sub> </sub>= -198 kJ SO<sub>2</sub>(g) -297 A) -792 kJ mol<sup>-1</sup> B) -248 kJ mol<sup>-1</sup> C) -495 kJ mol<sup>-1</sup> D) -578 kJ mol<sup>-1</sup> E) -396 kJ mol<sup>-1</sup> H° information provided to calculate Use the H° and H°<sub> </sub>information provided to calculate H° for SO<sub>3</sub>(g) : H°<sub> </sub>(kJ ) 2SO<sub>2</sub>(g) + O<sub>2</sub>(g) → 2SO<sub>3</sub>(g) H°<sub> </sub>= -198 kJ SO<sub>2</sub>(g) -297 A) -792 kJ mol<sup>-1</sup> B) -248 kJ mol<sup>-1</sup> C) -495 kJ mol<sup>-1</sup> D) -578 kJ mol<sup>-1</sup> E) -396 kJ mol<sup>-1</sup> H° for SO3(g) : Use the H° and H°<sub> </sub>information provided to calculate H° for SO<sub>3</sub>(g) : H°<sub> </sub>(kJ ) 2SO<sub>2</sub>(g) + O<sub>2</sub>(g) → 2SO<sub>3</sub>(g) H°<sub> </sub>= -198 kJ SO<sub>2</sub>(g) -297 A) -792 kJ mol<sup>-1</sup> B) -248 kJ mol<sup>-1</sup> C) -495 kJ mol<sup>-1</sup> D) -578 kJ mol<sup>-1</sup> E) -396 kJ mol<sup>-1</sup> H° (kJ Use the H° and H°<sub> </sub>information provided to calculate H° for SO<sub>3</sub>(g) : H°<sub> </sub>(kJ ) 2SO<sub>2</sub>(g) + O<sub>2</sub>(g) → 2SO<sub>3</sub>(g) H°<sub> </sub>= -198 kJ SO<sub>2</sub>(g) -297 A) -792 kJ mol<sup>-1</sup> B) -248 kJ mol<sup>-1</sup> C) -495 kJ mol<sup>-1</sup> D) -578 kJ mol<sup>-1</sup> E) -396 kJ mol<sup>-1</sup> ) 2SO2(g) + O2(g) → 2SO3(g) Use the H° and H°<sub> </sub>information provided to calculate H° for SO<sub>3</sub>(g) : H°<sub> </sub>(kJ ) 2SO<sub>2</sub>(g) + O<sub>2</sub>(g) → 2SO<sub>3</sub>(g) H°<sub> </sub>= -198 kJ SO<sub>2</sub>(g) -297 A) -792 kJ mol<sup>-1</sup> B) -248 kJ mol<sup>-1</sup> C) -495 kJ mol<sup>-1</sup> D) -578 kJ mol<sup>-1</sup> E) -396 kJ mol<sup>-1</sup> H° = -198 kJ SO2(g) -297

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