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A Dihybrid Testcross Is Made to Determine If Genes C

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A dihybrid testcross is made to determine if genes C and D are linked.The results are shown in the table.
 Parent genotypes: Ccnbsp;Dd×ccddCcnbsp;Dd222Ccnbsp;dd280 Progeny genotypes: ccnbsp;Dd280ccnbsp;dd2181000\begin{array}{|l|c|r|}\hline \text { Parent genotypes: } & C c &nbsp;D d \times c c d d & \\\hline & C c&nbsp; D d & 222 \\\hline & C c &nbsp;d d & 280 \\\hline \text { Progeny genotypes: } & c c &nbsp;D d & 280 \\\hline & c c &nbsp;d d & 218 \\\hline & & 1000 \\\hline\end{array}  A dihybrid testcross is made to determine if genes C and D are linked.The results are shown in the table.   \begin{array}{|l|c|r|} \hline \text { Parent genotypes: } & C c  D d \times c c d d & \\ \hline & C c  D d & 222 \\ \hline & C c  d d & 280 \\ \hline \text { Progeny genotypes: } & c c  D d & 280 \\ \hline & c c  d d & 218 \\ \hline & & 1000 \\ \hline \end{array}    -The chi-square value is the sum for all progeny classes of (observed-expected) <sup>2</sup>/expected.Using the chi-square test for goodness of fit, calculate the chi-square value to test the null hypothesis that genes C and D are unlinked.What is the chi-square value? A) 0 B) 0.0576 C) 10.8 D) 14.4 E) cannot be determined
-The chi-square value is the sum for all progeny classes of (observed-expected) 2/expected.Using the chi-square test for goodness of fit, calculate the chi-square value to test the null hypothesis that genes C and D are unlinked.What is the chi-square value?


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