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The Network Shown Is Assembled with Uncharged Capacitors X CX=3.0μFC _ { X } = 3.0 \mu \mathrm { F } \text {, }

question 98

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The network shown is assembled with uncharged capacitors X , Y, and Z, with CX=3.0μFC _ { X } = 3.0 \mu \mathrm { F } \text {, } CY=5.0μF\mathrm { C } _ { \mathrm { Y } } = 5.0 \mu \mathrm { F } and CZ=1.0μFC _ { Z } = 1.0 \mu \mathrm { F } The switches S1 and S2 are initially open, and a potential difference Vab = 120 V is applied between points a and b. After the network is assembled, switch S1 is then closed, but switch S2 is kept open. What is the final potential difference across capacitor Z?  The network shown is assembled with uncharged capacitors X , Y, and Z, with  C _ { X } = 3.0 \mu \mathrm { F } \text {, }   \mathrm { C } _ { \mathrm { Y } } = 5.0 \mu \mathrm { F }  and  C _ { Z } = 1.0 \mu \mathrm { F }  The switches S<sub>1</sub> and S<sub>2</sub> are initially open, and a potential difference V<sub>ab</sub> = 120 V is applied between points a and b. After the network is assembled, switch S<sub>1</sub> is then closed, but switch S<sub>2</sub> is kept open. What is the final potential difference across capacitor Z?   A) 100 V B) 600 V C) 55 V D) 38 V E) 29 V


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