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A Bacterium of Genotype A+b+c+d+ Is the Donor in a Cotransformation

question 65

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A bacterium of genotype a+b+c+d+ is the donor in a cotransformation mapping. The recipient is a-b-c-d-. Data from the transformed cells (genotype and percent of each cotransformant) are shown below. What is the order of the genes?  Genotype  Cotransformants a+and b+2%a+and c+0%a+and d+5%b+and c+5%b+and a+0%c+and d+0%\begin{array} { l c } \text { Genotype } & \text { Cotransformants } \\a ^ { + } \text {and } b ^ { + } & 2 \% \\a ^ { + } \text {and } c ^ { + } & 0 \% \\a ^ { + } \text {and } d ^ { + } & 5 \% \\b ^ { + } \text {and } c ^ { + } & 5 \% \\b ^ { + } \text {and } a ^ { + } & 0 \% \\c ^ { + } \text {and } d ^ { + } & 0 \%\end{array}


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