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For the Simple Harmonic Motion Described by the Trigonometric Function d=9cos8π5td = 9 \cos \frac { 8 \pi } { 5 } t

question 120

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For the simple harmonic motion described by the trigonometric function, find the frequency per second.
d=9cos8π5td = 9 \cos \frac { 8 \pi } { 5 } t


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