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The Horizontal Distance D (In Feet) Traveled by a Projectile d=v232sin2θd = \frac { v ^ { 2 } } { 32 } \sin 2 \theta

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The horizontal distance d (in feet) traveled by a projectile with an initial speed of v feet per second is modeled by d=v232sin2θd = \frac { v ^ { 2 } } { 32 } \sin 2 \theta , where θ\theta is the angle at which the projectile is launched.
Find the horizontal distance traveled by a golf ball that is hit with an initial speed of 80 feet per second when the ball is hit at an angle of θ=60\theta = 60 ^ { \circ } .Round to the nearest foot.


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