Find the Limit (If It Exists) $\lim _ { x \rightarrow 0 } \frac { \frac { 1 } { x + 3 } - \frac { 1 } { 3 } } { x }$

question 188

Multiple Choice

Find the limit (if it exists) .Use a graphing utility to verify your result graphically. $\lim _ { x \rightarrow 0 } \frac { \frac { 1 } { x + 3 } - \frac { 1 } { 3 } } { x }$

• A) \(\lim _ { x \rightarrow 0 } \frac { \frac { 1 } { x + 3 } - \frac { 1 } { 3 } } { x } = \frac { 1 } { 12 }\)
• B) \(\lim _ { x \rightarrow 0 } \frac { \frac { 1 } { x + 3 } - \frac { 1 } { 3 } } { x } = - \frac { 1 } { 12 }\)
• C) \(\lim _ { x \rightarrow 0 } \frac { \frac { 1 } { x + 3 } - \frac { 1 } { 3 } } { x } = \frac { 1 } { 3 }\)
• D) \(\lim _ { x \rightarrow 0 } \frac { \frac { 1 } { x + 3 } - \frac { 1 } { 3 } } { x } = - \frac { 1 } { 9 }\)
• E) \(\lim _ { x \rightarrow 0 } \frac { \frac { 1 } { x + 3 } - \frac { 1 } { 3 } } { x } = \frac { 1 } { 9 }\)

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