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TABLE 14-8
a Financial Analyst Wanted to Examine SUMMARY OUTPUT\text {SUMMARY OUTPUT}

question 78

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TABLE 14-8
A financial analyst wanted to examine the relationship between salary (in $1,000) and 4 variables: age (X1 = Age), experience in the field (X2 = Exper), number of degrees (X3 = Degrees), and number of previous jobs in the field (X4 = Prevjobs). He took a sample of 20 employees and obtained the following Microsoft Excel output:
SUMMARY OUTPUT\text {SUMMARY OUTPUT}
 Regression Statistics  Multiple R 0.992 R Square0.984 Adjusted R Square0.979 Standard Error 2.26743 Observations20\begin{array}{ll}\hline \text { Regression Statistics } \\\hline \text { Multiple R }& 0.992 \\ \text { R Square} & 0.984 \\ \text { Adjusted R Square} & 0.979 \\ \text { Standard Error }& 2.26743 \\ \text { Observations} & 20 \\\hline\end{array}

ANOVA
d f  SS  M S  F Significance F  Regression44609.831641152.45791224.1600.0001Residual1577.118365.14122Total194686.95000\begin{array}{lccclc}\hline & \text {d f }& \text { SS }& \text { M S } & \text { F } & \text {Significance F } \\\hline \text { Regression} & 4 & 4609.83164& 1152.45791 & 224.160& 0.0001 \\ \text {Residual} &15& 77.11836 & 5.14122& & \\ \text {Total} & 19 & 4686.95000 & & & \\\hline\end{array}

Coefficients Standard Error t Stat  p -value Intercept 9.6111982.779886383.4570.0035 Age 1.3276950.1149193011.5530.0001 Exper 0.1067050.142655590.7480.4660 Degrees7.3113320.803241879.1020.0001 Prevjobs 0.5041680.447715731.1260.2778\begin{array}{lrrrr}\hline & \text {Coefficients} &\text { Standard Error} & \text { t Stat } & \text { p -value} \\\hline \text { Intercept }& -9.611198 & 2.77988638 & -3.457 & 0.0035 \\\text { Age }& 1.327695 & 0.11491930 & 11.553 & 0.0001 \\\text { Exper }& -0.106705 & 0.14265559 & -0.748 & 0.4660 \\\text { Degrees} & 7.311332 & 0.80324187 & 9.102 & 0.0001 \\\text { Prevjobs }& -0.504168 & 0.44771573 & -1.126 & 0.2778 \\\hline\end{array}

-Referring to Table 14-8, the analyst wants to use a t test to test for the significance of the coefficient of X3. The p-value of the test is _____.


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