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In Reference to the Equation =1.860.51x1+0.60x2 = 1.86 - 0.51 x _ { 1 } + 0.60 \quad x _ { 2 }

question 92

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In reference to the equation  In reference to the equation    = 1.86 - 0.51 x _ { 1 } + 0.60 \quad x _ { 2 }   , the value 0.60 is the change in  y  per unit change in  x _ { 2 }  , regardless of the value of  x _ { 1 }  . =1.860.51x1+0.60x2 = 1.86 - 0.51 x _ { 1 } + 0.60 \quad x _ { 2 }
, the value 0.60 is the change in yy per unit change in x2x _ { 2 } , regardless of the value of x1x _ { 1 } .


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