$\int \frac{1}{4-y^{2}} d y=-\frac{1}{4}(\ln |y-2|+\ln |y+2|)+C$

question 48

True/False

$\int \frac{1}{4-y^{2}} d y=-\frac{1}{4}(\ln |y-2|+\ln |y+2|)+C$ .

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