If $f(x)=\frac{x}{2}+4$ And G(x)= X + 1, How Do $\int_{8}^{12} f(x) d x$

question 1

Multiple Choice

If $f(x) =\frac{x}{2}+4$ and g(x) = x + 1, how do $\int_{8}^{12} f(x) d x$ and $\int_{8}^{12} g(x) d x$ compare?

• A) \(\int_{8}^{12} f(x) d x\) < \(\int_{8}^{12} g(x) d x\)
• B) \(\int_{8}^{12} f(x) d x\) > \(\int_{8}^{12} g(x) d x\)
• C) \(\int_{8}^{12} f(x) d x\) = \(\int_{8}^{12} g(x) d x\)

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