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The Average Value of a Function G on 0 \le X \le

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The average value of a function g on 0 \le x \le 2 is a constant gˉ\bar{g} given by gˉ=12002g(d) dx\bar{g}=\frac{1}{2-0} \int_{0}^{2} g(d) d x .Also, 02(g(x) gˉ) 2dx0\int_{0}^{2}(g(x) -\bar{g}) ^{2} d x \geq 0 , since (g(x) gˉ) 2(g(x) -\bar{g}) ^{2} is a square.Which of the following must be true?


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