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The Following MINITAB Output Presents a 95% Confidence Interval Find the Sample Size Needed So That the 99% Confidence

question 24

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The following MINITAB output presents a 95% confidence interval.
 The assumed sigma =8.0573 Variable N Mean  SE Mean 95%CIx5253.5631.1173(51.373,55.753) \begin{array}{crccc}\hline{\text { The assumed sigma }=8.0573} \\\text { Variable } & \mathrm{N} & \text { Mean } & \text { SE Mean } & 95 \% \mathrm{CI} \\\mathrm{x} & 52 & 53.563 & 1.1173 & (51.373,55.753) \\\hline\end{array}
Find the sample size needed so that the 99% confidence interval will have a margin of error of
1.1.


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