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Solve the Linear Congruence 15x31(mod47) given that the inverse of 15 modulo 47 is 2215 x \equiv 31 ( \bmod 47 ) \text { given that the inverse of } 15 \text { modulo } 47 \text { is } 22 \text {. }

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Solve the linear congruence 15x31(mod47) given that the inverse of 15 modulo 47 is 2215 x \equiv 31 ( \bmod 47 ) \text { given that the inverse of } 15 \text { modulo } 47 \text { is } 22 \text {. }


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