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Use the Principle of Mathematical Induction to Prove That 1+4+7+10++(3n2)=n(3n1)2 for all 1 + 4 + 7 + 10 + \cdots + ( 3 n - 2 ) = \frac { n ( 3 n - 1 ) } { 2 } \text { for all }

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Use the Principle of Mathematical Induction to prove that 1+4+7+10++(3n2)=n(3n1)2 for all 1 + 4 + 7 + 10 + \cdots + ( 3 n - 2 ) = \frac { n ( 3 n - 1 ) } { 2 } \text { for all } n ≥ 1.


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