Solve Using Cramer's Rule $= 3.5 \mathrm {~m}$ , Length $= 6 \mathrm {~m}$

question 41

Multiple Choice

Solve using Cramer's Rule.
-The perimeter of a rectangle is 19 meters. If the width is doubled and the length is tripled, the perimeter is 50 meters. Determine the original width and length.

• A) width \(= 3.5 \mathrm {~m}\), length \(= 6 \mathrm {~m}\)
• B) width \(= 8 \mathrm {~m}\), length \(= 17 \mathrm {~m}\)
• C) width \(= 6 \mathrm {~m}\), length \(= 10 \mathrm {~m}\)
• D) width \(= 7 \mathrm {~m}\), length \(= 12 \mathrm {~m}\)

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