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Decide What Values of the Variable Cannot Possibly Be Solutions 1x31x+7=12\frac { 1 } { x - 3 } - \frac { 1 } { x + 7 } = 12

question 3

Multiple Choice

Decide what values of the variable cannot possibly be solutions for the equation.
- 1x31x+7=12\frac { 1 } { x - 3 } - \frac { 1 } { x + 7 } = 12


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