Decide What Values of the Variable Cannot Possibly Be Solutions $$\frac { x } { x - 3 } + \frac { 1 } { x + 9 } = \frac { 12 } { x ^ { 2 } + 6 x - 27 }$$

question 462

Multiple Choice

Decide what values of the variable cannot possibly be solutions for the equation.
- $$\frac { x } { x - 3 } + \frac { 1 } { x + 9 } = \frac { 12 } { x ^ { 2 } + 6 x - 27 }$$

• A) \(- 9,3\)
• B) \(- 3,0,9\)
• C) \(- 3,9 , - 27\)
• D) \(- 9,0,3\)

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