The Model $\sqrt{\widehat{\text { distance }}}$ = 330 + 0235 (Speed $65 \mathrm { mph }$

question 7

Multiple Choice

The model $\sqrt{\widehat{\text { distance }}}$ = 3.30 + 0.235 (speed. can be used to predict the stopping distance (in feet. for a car traveling at a specific speed (in mph.) According to this model, about how much distance will a car going $65 \mathrm { mph }$ need to stop?

• A) \(729.0\) feet
• B) \(345.0\) feet
• C) \(27.0\) feet
• D) \(4.3\) feet
• E) \(18.6\) feet