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Use the Partial Table Below to Find the P-Value That  Standard Score and Percentiles for a Normal Distribution  \underline{\text { Standard Score and Percentiles for a Normal Distribution }}

question 62

Multiple Choice

Use the partial table below to find the P-value that corresponds to the standard z-score, and determine whether the
alternative hypothesis is supported or not supported at the 0.05 significance level.  Standard Score and Percentiles for a Normal Distribution  \underline{\text { Standard Score and Percentiles for a Normal Distribution }}
Z% Z%Z%3.50.021.015.871.593.323.00.130.530.852.097.722.50.620.050.002.599.382.02.280.569.153.099.871.56.681.084.133.599.98\begin{array}{rlrlll}\underline{Z }&\underline{ \% }\ &\underline{ Z }& \underline{\% }&\underline{Z }& \underline{\%}\\ -3.5 & 0.02 & -1.0 & 15.87 & 1.5 & 93.32 \\-3.0 & 0.13 & -0.5 & 30.85 & 2.0 & 97.72 \\-2.5 & 0.62 & 0.0 & 50.00 & 2.5 & 99.38 \\-2.0 & 2.28 & 0.5 & 69.15 & 3.0 & 99.87 \\-1.5 & 6.68 & 1.0 & 84.13 & 3.5 & 99.98\end{array}

- z=2.5\mathrm { z } = - 2.5 for Ha:μ0.861\mathrm { H } _ { \mathrm { a } } : \mu \neq 0.861


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