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Solve the Equation on the Interval 0θ<2π0 \leq \theta < 2 \pi

question 375

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Solve the equation on the interval 0θ<2π0 \leq \theta < 2 \pi
- sin2θcos2θ=0\sin ^ { 2 } \theta - \cos ^ { 2 } \theta = 0


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