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Solve the Equation for Solutions in the Interval [0°, 360°) cos2θ=32\cos 2 \theta = \frac { \sqrt { 3 } } { 2 }

question 63

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Solve the equation for solutions in the interval [0°, 360°) . Round to the nearest degree.
- cos2θ=32\cos 2 \theta = \frac { \sqrt { 3 } } { 2 }


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