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When a Neutron Collides with a Uranium-235 Nucleus It Can

question 36

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When a neutron collides with a uranium-235 nucleus it can induce a variety of fission reactions.
One such reaction is
92235U+01n54140Xe+3894Sr+201n{ } _ { 92 } ^ { 235 } \mathrm { U } + { } _ { 0 } ^ { 1 } \mathrm { n } \rightarrow { } _ { 54 } ^ { 140 } \mathrm { Xe } + { } _ { 38 } ^ { 94 } \mathrm { Sr } + 2 { } _ { 0 } ^ { 1 } \mathrm { n }
The following mass values are known:
54140 Xe: 139.921620u3894Sr:93.915367u92235U:235.043924u01n:1.008665u\begin{array} { l l } { } _ { 54 } ^ { 140 } \text { Xe: } & 139.921620 \mathrm { u } \\{ } _ { 38 } ^ { 94 } \mathrm { Sr } : & 93.915367 \mathrm { u } \\{ } _ { 92 } ^ { 235 } \mathrm { U } : & 235.043924 \mathrm { u } \\{ } _ { 0 } ^ { 1 } \mathrm { n } : & 1.008665 \mathrm { u }\end{array}
What mass of uranium is needed to produce a 10-kiloton yield? (1u=931.5MeV/c2=1.66054×\left( 1 \mathrm { u } = 931.5 \mathrm { MeV } / c ^ { 2 } = 1.66054 \times \right. 1027 kg10 ^ { - 27 } \mathrm {~kg} , 1-kiloton yield =5.0×1012 J= 5.0 \times 10 ^ { 12 } \mathrm {~J} )


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