For a Certain Metal, Light of Frequency $7.24 \times 10 ^ { - 14 } \mathrm {~Hz}$

question 1

Short Answer

For a certain metal, light of frequency $7.24 \times 10 ^ { - 14 } \mathrm {~Hz}$ is just barely able to dislodge photoelectrons from the metal. $\left( h = 6.626 \times 10 ^ { - 34 } \mathrm {~J} \cdot \mathrm { s } , 1 \mathrm { eV } = 1.60 \times 10 ^ { - 19 } \mathrm {~J} , e = 1.60 \times \right.$ $10 ^ { - 19 } \mathrm { C }$ )
(a) What will be the stopping potential if light of frequency $8.75 \times 10 ^ { - 14 } \mathrm {~Hz}$ is shone on the metal?
(b) What is the work function (in electron-volts) of this metal?

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