A Proton Moving with a Velocity Of $4.0 \times 10 ^ { 4 } \mathrm {~m} / \mathrm { s }$

question 70

Multiple Choice

A proton moving with a velocity of $4.0 \times 10 ^ { 4 } \mathrm {~m} / \mathrm { s }$ enters a magnetic field of $0.20 \mathrm {~T}$ . If the angle between the velocity of the proton and the direction of the magnetic field is $60 ^ { \circ }$ , what is the magnitude of the magnetic force on the proton? $\left( e = 1.60 \times 10 ^ { - 19 } \mathrm { C } \right)$

• A) \(0.60 \times 10 ^ { - 15 } \mathrm {~N}\)
• B) \(2.2 \times 10 ^ { - 15 } \mathrm {~N}\)
• C) \(1.1 \times 10 ^ { - 15 } \mathrm {~N}\)
• D) \(3.3 \times 10 ^ { - 15 } \mathrm {~N}\)
• E) \(1.8 \times 10 ^ { - 15 } \mathrm {~N}\)

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