After a Proton with an Initial Speed Of $1.50 \times 10 ^ { 5 } \mathrm {~m} / \mathrm { s }$

question 75

Multiple Choice

After a proton with an initial speed of $1.50 \times 10 ^ { 5 } \mathrm {~m} / \mathrm { s }$ has increased its speed by accelerating through a potential difference of $0.100 \mathrm { kV }$ , what is its final speed? $\left( e = 1.60 \times 10 ^ { - 19 } \mathrm { C } , m _ { \text {proton } } = \right.$ $1.67 \times 10 ^ { - 27 } \mathrm {~kg}$ )

• A) \(1.55 \times 10^6 \mathrm {~m} / \mathrm { s }\)
• B) \(2.04 \times 10 ^ { 5 } \mathrm {~m} / \mathrm { s }\)
• C) \(8.80 \times 10 ^ { 5 } \mathrm {~m} / \mathrm { s }\)
• D) \(4.56 \times 10 ^ { 5 } \mathrm {~m} / \mathrm { s }\)
• E) \(3.55 \times 10 ^ { 5 } \mathrm {~m} / \mathrm { s }\)

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