Solve
-A Local Pond Can Only Hold Up to 53 $\frac { \mathrm { dP } } { \mathrm { dt } } = ( 0.0015 ) ( 53 - \mathrm { P } ) \mathrm { P }$

question 72

Multiple Choice

Solve.
-A local pond can only hold up to 53 geese. Seven geese are introduced into the pond. Assume that the rate of grow th of the population is $\frac { \mathrm { dP } } { \mathrm { dt } } = ( 0.0015 ) ( 53 - \mathrm { P } ) \mathrm { P }$ where $t$ is time in weeks. How long will it take for the goose population to be 25 ?

• A) 22.26 weeks
• B) 46.73 weeks
• C) 26.02 weeks
• D) 14.23 weeks

---

Definitions:

Conjugate Acid

The species formed when a base gains a proton (H+), effectively showing the protonated form of the base.

Conjugate Base

The species that remains after a Bronsted-Lowry acid has donated a proton, capable of accepting a proton to reform the acid.

Acid/Base Reaction

A chemical reaction that involves the transfer of protons (H+) between a base (proton acceptor) and an acid (proton donor).

Basicity

A measure of the ability of a substance to accept hydrogen ions (protons), often used to describe the strength of bases.