Identify Equilibrium Values and Determine Which Are Stable and Which $$\frac { \mathrm { dy } } { \mathrm { dx } } = ( \mathrm { y } + 5 ) ( \mathrm { y } + 4 )$$

question 27

Multiple Choice

Identify equilibrium values and determine which are stable and which are unstable.
- $$\frac { \mathrm { dy } } { \mathrm { dx } } = ( \mathrm { y } + 5 ) ( \mathrm { y } + 4 )$$

• A) y = 4 is a stable equilibrium value and y = -5 is an unstable equilibrium.
• B) y = -5 is a stable equilibrium value and y = 4 is an unstable equilibrium.
• C) y = -4 is a stable equilibrium value and y = 5 is an unstable equilibrium.
• D) y = 5 is a stable equilibrium value and y = 4 is an unstable equilibrium.

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Vigorous Activity

Physical activities that require a high level of energy expenditure, often resulting in rapid breathing and a substantial increase in heart rate.

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