Solve the Initial Value Problem for Y as a Function $$\sqrt { x ^ { 2 } - 4 } \frac { d y } { d x } = x , x > 2 , y ( 4 ) = 0$$

question 446

Multiple Choice

Solve the initial value problem for y as a function of x.
- $$\sqrt { x ^ { 2 } - 4 } \frac { d y } { d x } = x , x > 2 , y ( 4 ) = 0$$

• A) \(y = \sqrt { x ^ { 2 } - 4 } - 2 \sqrt { 3 }\)
• B) \(y = \sqrt { x ^ { 2 } - 4 }\)
• C) \(y = \frac { \sqrt { x ^ { 2 } - 4 } } { x }\)
• D) \(y = \frac { \sqrt { x ^ { 2 } - 4 } } { x } - \frac { \sqrt { 3 } } { 2 }\)

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