Solve the Initial Value Problem for Y as a Function $$x \sqrt { x ^ { 2 } - 4 } \frac { d y } { d x } = 1 , x > 2 , y ( 4 ) = 0$$

question 61

Multiple Choice

Solve the initial value problem for y as a function of x.
- $$x \sqrt { x ^ { 2 } - 4 } \frac { d y } { d x } = 1 , x > 2 , y ( 4 ) = 0$$

• A) \(y = \frac { 1 } { 2 } \sin ^ { - 1 } \frac { x } { 2 } + \frac { \pi } { 6 }\)
• B) \(y = \frac { 1 } { 2 } \sec ^ { - 1 } \frac { x } { 2 }\)
• C) \(y = \sec ^ { - 1 } \frac { x } { 2 } - \frac { \pi } { 3 }\)
• D) \(y = \frac { 1 } { 2 } \sec ^ { - 1 } \frac { x } { 2 } - \frac { \pi } { 6 }\)

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