Find the Absolute Extreme Values of the Function on the Interval

question 174

Multiple Choice

Find the absolute extreme values of the function on the interval.
- $$f ( x ) = \tan x , - \frac { \pi } { 6 } \leq x \leq \frac { \pi } { 6 }$$

• A) absolute maximum is \(\frac { \sqrt { 3 } } { 3 }\) at \(x = \frac { \pi } { 6 }\) and \(- \frac { \pi } { 6 }\); absolute minimum does not exist
• B) absolute maximum is \(- \frac { \sqrt { 3 } } { 3 }\) at \(x = \frac { \pi } { 6 }\); absolute minimum is \(\frac { \sqrt { 3 } } { 3 }\) at \(x = - \frac { \pi } { 6 }\)
• C) absolute maximum is \(\frac { \sqrt { 3 } } { 3 }\) at \(x = \frac { 2 \pi } { 18 }\); absolute minimum is \(- \frac { \sqrt { 3 } } { 3 }\) at \(x = - \frac { \pi } { 12 }\)
• D) absolute maximum is \(\frac { \sqrt { 3 } } { 3 }\) at \(x = \frac { \pi } { 6 }\); absolute minimum is \(- \frac { \sqrt { 3 } } { 3 }\) at \(x = - \frac { \pi } { 6 }\)

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