Solve the Problem $x ^ { 2 } + y ^ { 2 } + z ^ { 2 } = 4$

question 214

Multiple Choice

Solve the problem.
-Find the point on the sphere $x ^ { 2 } + y ^ { 2 } + z ^ { 2 } = 4$ that is farthest from the point $( 3,1 , - 1 )$ .

• A) \(\left( - \frac { 6 } { \sqrt { 11 } } , - \frac { 2 } { \sqrt { 11 } } , - \frac { 2 } { \sqrt { 11 } } \right)\)
• B) \(\left( - \frac { 6 } { \sqrt { 11 } } , \frac { 2 } { \sqrt { 11 } } , - \frac { 2 } { \sqrt { 11 } } \right)\)
• C) \(\left( - \frac { 6 } { \sqrt { 11 } } , \frac { 2 } { \sqrt { 11 } } , \frac { 2 } { \sqrt { 11 } } \right)\)
• D) \(\left\{ - \frac { 6 } { \sqrt { 11 } } , - \frac { 2 } { \sqrt { 11 } } , \frac { 2 } { \sqrt { 11 } } \right)\)

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