Solve the Problem $x ^ { 2 } + y ^ { 2 } + 2 z = 4$

question 6

Multiple Choice

Solve the problem.
-Find the point on the curve of intersection of the paraboloid $x ^ { 2 } + y ^ { 2 } + 2 z = 4$ and the plane $x - y + 2 z = 0$ that is farthest from the origin.

• A) (-2, 2, 2)
• B) (2, -2, -2)
• C) (2, -2, 2)
• D) (-2, -2, 2)

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