The Position Vector of a Particle Is R(t) $t = \frac { \pi } { 8 }$

question 126

Multiple Choice

The position vector of a particle is r(t) . Find the requested vector.
-The acceleration at $t = \frac { \pi } { 8 }$ for $\mathbf { r } ( \mathrm { t } ) = \left( 10 \mathrm { t } - 3 \mathrm { t } ^ { 3 } \right) \mathbf { i } + 2 \tan ( 2 \mathrm { t } ) \mathbf { j } + \mathrm { e } ^ { 5 } \mathrm { t } \mathbf { k }$

• A) \(a \left( \frac { \pi } { 8 } \right) = - \frac { 9 } { 4 } \pi i \mathbf { i } - 32 \mathbf { j } + 25 \mathbf { k }\)
• B) \(a \left( \frac { \pi } { 8 } \right) = \frac { 9 } { 4 } \pi \mathbf { i } + 32 \mathbf { j } + 25 \mathrm { e } ^ { 5 / 8 } \pi \mathbf { k }\)
• C) \(a \left( \frac { \pi } { 8 } \right) = - \frac { 9 } { 4 } \pi \mathrm { i } + 32 \mathrm { j } + 25 \mathrm { e } ^ { 5 / 8 \pi } \mathbf { k }\)
• D) \(a \left( \frac { \pi } { 8 } \right) = - \frac { 9 } { 4 } \pi i - 32 j + 25 e ^ { 5 / 8 } \pi k\)

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