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Solve the Problem =8872 km= 8872 \mathrm {~km} Calculate the Period of the Satellite

question 22

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Solve the problem.
-The orbit of a satellite had a semimajor axis of a =8872 km= 8872 \mathrm {~km} . Calculate the period of the satellite. (Earth's mass =5.975×1024 kg= 5.975 \times 10 ^ { 24 } \mathrm {~kg} and G=6.6720×1011Nm2 kg2\mathrm { G } = 6.6720 \times 10 ^ { - 11 } \mathrm { Nm } ^ { 2 } \mathrm {~kg} - 2 ) .


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