The Vector R(t) Is the Position Vector of a Particle$\mathbf{r}(\mathrm{t})=\mathrm{e}^{6 \mathrm{t}_{\mathrm{i}}+\left(4+\mathrm{e}^{-6 \mathrm{t}}\right) \mathrm{j}+(7 \cos 8 \mathrm{t}) \mathbf{k}}$

Question

Examlex · Accepted Answer

The Answer of The Vector R(t) Is the Position Vector of a Particle$\mathbf{r}(\mathrm{t})=\mathrm{e}^{6 \mathrm{t}_{\mathrm{i}}+\left(4+\mathrm{e}^{-6 \mathrm{t}}\right) \mathrm{j}+(7 \cos 8 \mathrm{t}) \mathbf{k}}$

The Vector R(t) Is the Position Vector of a Particle $\mathbf{r}(\mathrm{t})=\mathrm{e}^{6 \mathrm{t}_{\mathrm{i}}+\left(4+\mathrm{e}^{-6 \mathrm{t}}\right) \mathrm{j}+(7 \cos 8 \mathrm{t}) \mathbf{k}}$

Definitions:

The Vector R(t) Is the Position Vector of a Particle r(t)=e6ti+(4+e−6t)j+(7cos⁡8t)k\mathbf{r}(\mathrm{t})=\mathrm{e}^{6 \mathrm{t}_{\mathrm{i}}+\left(4+\mathrm{e}^{-6 \mathrm{t}}\right) \mathrm{j}+(7 \cos 8 \mathrm{t}) \mathbf{k}}r(t)=e6ti​+(4+e−6t)j+(7cos8t)k

Definitions:

The Vector R(t) Is the Position Vector of a Particle $\mathbf{r}(\mathrm{t})=\mathrm{e}^{6 \mathrm{t}_{\mathrm{i}}+\left(4+\mathrm{e}^{-6 \mathrm{t}}\right) \mathrm{j}+(7 \cos 8 \mathrm{t}) \mathbf{k}}$