Solve the Problem $\mathbf { v } = \frac { 1 } { 3 } \mathbf { i } + \frac { 1 } { 3 } \mathbf { j } - \frac { 1 } { 3 } \mathbf { k }$

question 98

Multiple Choice

Solve the problem.
-Find a vector of magnitude 9 in the direction opposite to the direction of $\mathbf { v } = \frac { 1 } { 3 } \mathbf { i } + \frac { 1 } { 3 } \mathbf { j } - \frac { 1 } { 3 } \mathbf { k }$ .

• A) \(9 \sqrt { 3 } \left( - \frac { 1 } { 3 } i - \frac { 1 } { 3 } j + \frac { 1 } { 3 } k \right)\)
• B) \(9 \sqrt { 3 } \left( \frac { 1 } { 3 } \mathbf { i } + \frac { 1 } { 3 } \mathbf { j } - \frac { 1 } { 3 } \mathbf { k } \right)\)
• C) \(9 \left( \frac { 1 } { 3 } \mathbf { i } + \frac { 1 } { 3 } \mathrm { j } - \frac { 1 } { 3 } \mathbf { k } \right)\)
• D) \(9 \left( - \frac { 1 } { 3 } \mathbf { i } - \frac { 1 } { 3 } \mathbf { j } + \frac { 1 } { 3 } \mathbf { k } \right)\)

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Definitions:

Complementary Products

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Substitute Products

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Cross Elasticity of Demand

A measure of how the quantity demanded of one good responds to a price change of another good, showing the interdependence of demands.

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